$X e F_{6}$ is hydrolysed to $X e O_{3}$ as:
$X e F_{6} + H_{2} O ⟶ . . . . . . . . . . . (I)$

I : X e O F_{4}

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I : X e_{2} O_{3} F_{6}

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I : X e O_{2} F_{2}

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none of these

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Solution

The correct option is A $I : X e O F_{4}$
$X e F_{6}$ is hydrolysed to $X e O_{3}$ in following steps
$X e F_{6} + 3 H_{2} O \to X e O_{3} + 6 H F$
$X e O F_{4} + 2 H_{2} O \to X e O_{3} + 4 H F$
Hence option A is correct.

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Similar questions

X e F_{6} + H_{2} O ⟶ I + A

Q. Assertion :

X e F_{6}

cannot be handled in glass or quartz apparatus. Reason: Reaction between

X e F_{6}

and

S i O_{2}

of glass form explosive

X e O_{3}

Q. In the given reaction

X e F_{6} + . . . . . . . . ⟶ X e O_{3} + H F

Complete the reaction

Xenon forms three binary fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ . All the three fluorides are colourless crystalline solids sublimating at 295K. They are powerful fluorinating agents and they are readily hydrolysed by water.
$X e O_{3}$ is a colorless explosive solid acid, prepared by

X e F_{6}

reacts with quartz forming

X e O_{3}

2 X e F_{6} + x S i O_{2} ⟶

What is value of

x

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XeF6 is hydrolysed to XeO3 as:XeF6+H2O⟶...........(I)

The correct option is A I:XeOF4XeF6 is hydrolysed to XeO3 in following stepsXeF6+3H2O→XeO3+6HFXeOF4+2H2O→XeO3+4HFHence option A is correct.

$X e F_{6}$ is hydrolysed to $X e O_{3}$ as:
$X e F_{6} + H_{2} O ⟶ . . . . . . . . . . . (I)$

The correct option is A $I : X e O F_{4}$
$X e F_{6}$ is hydrolysed to $X e O_{3}$ in following steps
$X e F_{6} + 3 H_{2} O \to X e O_{3} + 6 H F$
$X e O F_{4} + 2 H_{2} O \to X e O_{3} + 4 H F$
Hence option A is correct.