$X e F_{6}$ on hydrolysis gives:

X e O_{3}

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X e O_{2}

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X e O

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X e

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Solution

The correct option is A $X e O_{3}$
$X e F_{6} + H_{2} O \to X e O F_{4} + 2 H F$
$X e O F_{4} + H_{2} O \to X e O_{2} F_{2} + 2 H F$
$X e O_{2} F_{2} + H_{2} O \to X e O_{3} + 2 H F$
$X e F_{6}$ on hydrolysis gives $X e O_{3}$

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