$X e F_{6}$ on hydrolysis gives :

X e O F_{4}

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X e O_{2} F_{2}

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X e O_{3}

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X e O_{4}

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Solution

The correct options are
A $X e O F_{4}$
B $X e O_{2} F_{2}$
C $X e O_{3}$

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Similar questions

How are $X e O_{3}$ and $X e O_{4}$ prepared?

X e F_{6}

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

= k_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

= K_{2}

X e O_{4} + 2 H F ⇌ X e O_{3} F_{2} + H_{2} O

X e F_{6} + H_{2} O ⇌ X e O F_{4} + 2 H F

= K_{1}, X e O_{4} + X e F_{6} ⇌ X e O F_{4} + X e O_{3} F_{2}

= K_{2}

- X e O_{4} + 2 H F ⇌ X e O_{4} F_{2} + H_{2} O

X e O_{2} F_{2}, X e O F_{4}, X e F_{4}, X e F_{6}

X e

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