$X e F_{6}$ on partial hydrolysis with water produces a compound $X$ . The same compound $X$ is formed when $X e F_{6}$ reacts with silica. The compound $X$ is:

X e F_{2}

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X e F_{4}

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X e O_{3}

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X e O F_{4}

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Solution

The correct option is D $X e O F_{4}$
Partial hydrolysis of $X e F_{6}$ gives $X e O F_{4}$ (compound $X$ )
$X e F_{6} + H_{2} O \to X e O F_{4} + 2 H F$

$X e F_{6}$ reacts with silica $S i O_{2}$ to form $X e O F_{4}$ (compound $X$ )
$2 X e F_{6} + S i O_{2} \to 2 X e O F_{4} + S i F_{4}$

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1000^{\circ} C

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