All Xe fluorides are extremely strong oxidising agents. They are easily reduced to Xe by hydrogen.
XeF2+H2→2HF+Xe
XeF4+H2→4HF+Xe
XeF6+H2→6HF+Xe
They oxidise Cl− to chlorine and I− to iodides.
For example:
XeF2+2HCl→2HF+Cl2+Xe
XeF4+4Kl→2KF+2I2+Xe
"Alkali metals are good oxidizing agents."
Answer whether the above statement is true or false.
If true enter 1, else enter 0.