Xenon fluorides are very good oxidising and fluorinating agents. They also act as $F^{-}$ donors and acceptors. When $X e F_{4}$ donates its fluoride to $S b F_{5}$ , then the states of hybridisation of central atom of cationic part and anionic part product are :

s p^{3} d, s p^{3} d^{2}

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s p^{3} d^{2}, s p^{3} d

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s p^{3} d^{2}, s p^{3} d^{2}

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d s p^{2}, s p^{3}

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Solution

The correct option is A $s p^{3} d, s p^{3} d^{2}$
$\begin{matrix} [X e F_{3}]^{+} & [S b F_{6}]^{-} ↓ & ↓ s p^{3} d & s p^{3} d^{2} \end{matrix}$

$X e F_{3}^{+}$ has 3 bond bairs and two lone pairs
$S b F_{6}^{-}$ has 6 bond pairs

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Similar questions

Q. Xenon fluorides are very good oxidising and fluorinating agents. They also act as

F^{-}

donors and acceptors. When

X e F_{4}

donates its fluoride to

S b F_{5}

, then the states of hybridisation of central atom of cationic part and anionic part product are :

Q. The correct order of hybridization of the central atoms in the following species

X e F_{2}, X e F_{3}^{+}, X e F_{4}, X e F_{6}

Q. The Xenon Fluorides are very effective and clean Fluorinating agents. They also behave as good reducing agents – True or False?

Xenon forms three binary fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ . All the three fluorides are colourless crystalline solids sublimating at 295K. They are powerful fluorinating agents and they are readily hydrolysed by water.
The shape of $X e O_{3}$ is:

Pick out the correct statement with respect to $[M n (C N)_{6}]^{3 -}$

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Xenon fluorides are very good oxidising and fluorinating agents. They also act as F− donors and acceptors. When XeF4 donates its fluoride to SbF5, then the states of hybridisation of central atom of cationic part and anionic part product are :

The correct option is A sp3d,sp3d2[XeF3]+[SbF6]−↓↓sp3dsp3d2 XeF+3 has 3 bond bairs and two lone pairs SbF−6 has 6 bond pairs

Xenon fluorides are very good oxidising and fluorinating agents. They also act as $F^{-}$ donors and acceptors. When $X e F_{4}$ donates its fluoride to $S b F_{5}$ , then the states of hybridisation of central atom of cationic part and anionic part product are :

The correct option is A $s p^{3} d, s p^{3} d^{2}$
$\begin{matrix} [X e F_{3}]^{+} & [S b F_{6}]^{-} ↓ & ↓ s p^{3} d & s p^{3} d^{2} \end{matrix}$

$X e F_{3}^{+}$ has 3 bond bairs and two lone pairs
$S b F_{6}^{-}$ has 6 bond pairs