Xenon hexafluoride reacts with silica. How many orbitals are involved in the hybridisation of the xenon compound formed?

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Solution

$2 X e F_{6} + S i O_{2} \to 2 X e O F_{4} + S i F_{4}$

$X e O F_{4}$ has $s p^{3} d^{2}$ hybridisation. Hence a total of 6 orbitals are involved in hybridisation.

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(X e F_{6})

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