Xenon reacts with fluorine at $873 K$ and $7$ bar to form $X e F_{4}$ . In this reaction, the ratio of Xenon and fluorine required is:

1 : 5

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10 : 1

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1 : 3

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5 : 1

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Solution

The correct option is B $1 : 5$
When Xenon reacts with fluorine in a ratio of 1:5 at a temperature of 873 K it forms $X e F_{4}$

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Q. Xenon reacts with fluorine at 873 K and 7 bar to form

X e F_{4}

. In this reaction the ratio of Xenon and fluorine required is :

When Xenon reacts with fluorine in a ratio of 1:5 at a temperature of 873 K it forms:

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When xenon reacts with fluorine to form binary fluorides:

When 262 g of xenon (atomic mass = 131) reacted completely with 152 g of fluorine (atomic mass = 19), a mixture of XeF $_{2}$ and XeF $_{6}$ was produced. The molar ratio XeF $_{2}$ : XeF $_{6}$ is :

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Xenon reacts with fluorine at 873 K and 7 bar to form XeF4. In this reaction, the ratio of Xenon and fluorine required is:

The correct option is B 1:5 When Xenon reacts with fluorine in a ratio of 1:5 at a temperature of 873 K it forms XeF4

Xenon reacts with fluorine at $873 K$ and $7$ bar to form $X e F_{4}$ . In this reaction, the ratio of Xenon and fluorine required is:

The correct option is B $1 : 5$
When Xenon reacts with fluorine in a ratio of 1:5 at a temperature of 873 K it forms $X e F_{4}$