Question 89 (xii)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$9 x^{2} + 30 x + 25$

Open in App

Solution

We have, $9 x^{2} + 30 x + 25$
$= (3 x)^{2} + 2.3 x .5 + 5^{2} = (3 x + 5)^{2} = (3 x + 5) (3 x + 5)$

Suggest Corrections

Similar questions

a^{2} + 2 a b + b^{2} = (a + b)^{2}

9 x^{2} + 24 x + 16

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$ :

$9 x^{2} + 2 x y + \frac{y^{2}}{9}$

a^{2} - 2 a b + b^{2} = (a - b)^{2}

9 y^{2} - 4 x y + \frac{4 x^{2}}{9}

Question 92 (xii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{2}}{25} - 625$

a^{2} + 2 a b + b^{2} = (a + b)^{2}

4 x^{2} + 4 x + 1

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program