Using suitable identities, evaluate the following:

$98 \times 103$

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Solution

We have,
$98 \times 103 = (100 - 2) (100 + 3) = (100)^{2} + (- 2 + 3) 100 + (- 2) \times 3 = 10000 + 100 - 6$
$= 10094$ [using the identity, $(x + a) (x + b) = x^{2} + (a + b) x + a b$ ]

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