Question 91 (xiii)

Factorise the following:

$p^{2} - 16 p - 80$

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Solution

We have, $p^{2} - 16 p - 80$
$p^{2} - (20 - 4) p - 80 = p^{2} - 20 p + 4 p - 80 = p (p - 20) + 4 (p - 20) = (p - 20) (p + 4)$

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Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

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