Question 86 (xiii)
Using suitable identities, evaluate the following:
(9.9)2
We have, (9.9)2=(10−0.1)2=102+(0.1)2−2×10×0.1=100+0.01−2=98.01 [using the identity, (a−b)2=a2+b2−2ab]
Question 86 (iv)
(98)2
Question 86 (v)
(1005)2
Question 86 (vi)
(995)2
Question 86 (ii)
(49)2