Xin used $20 yd$ of fencing to build the walls of a square chicken coop. Which equation and solution represent $x$ , the length, in yards, of each wall of the square coop?

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Solution

Write the equation and solution of the length of the wall:
$20 yd$ of fencing to build the walls of a square coop.
Therefore, the perimeter of the square coop is $20 yd$ .
Then the equation of the perimeter of the square coop is $4 x = 20$ . $[∵ Perimeter of square = 4 \times side]$
Solving the equation,
$4 x = 20$ .
We get,
$x = 5 yd$ .
Hence, the equation of the square coop is $4 x = 20$ and the length is $5 yd$ .

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Xin used 20yd of fencing to build the walls of a square chicken coop. Which equation and solution represent x, the length, in yards, of each wall of the square coop?

Xin used $20 yd$ of fencing to build the walls of a square chicken coop. Which equation and solution represent $x$ , the length, in yards, of each wall of the square coop?