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Synthesis of Aldehydes and Ketones Using Carboxylic Acid and Its Derivatives

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Question

$N a B H_{4} \leftarrow --- - M e - C O O E T L i A I H_{4} - ---- \to$
Identify the products.

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Solution

$C H_{3} - C O O ε t N a B H_{4} \leftarrow --- - C H_{3} - C O O ε t L i A l H_{4} - --- \to C H_{3} - C H_{2} O H$
In case of ${N a B H}_{4}$ which is a mild reducing agent than ${L i A l H}_{4}$ . It only reduces aldehyde and ketone. So there will be no reaction through ${N a B H}_{4}$ .

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C H_{3} - C O - C H (R) - C O O E t (i) e t h a n o l i c K O H - --------- \to b o i l (i i) H_{3} O^{+}

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M e - \equiv - M e N a + L i q . N H_{3} - ------- \to + E t O H (B) B r_{2} / C C l_{4} - ----- \to C

Identify the compound C:

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Synthesis of Aldehydes and Ketones Using Carboxylic Acid and Its Derivatives

Standard XII Chemistry

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