You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IV

Mathematics

Addition of Roman Numerals

XLIV - XVII -...

Question

XLIV - XVII - XXII = ______

VII

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D V
Let us first convert the given Roman numerals into Hindu-Arabic numerals.

XLIV = 50 - 10 + 4 = 44
XVII = 10 + 5 + 1 + 1 = 17
XXII = 10 + 10 + 1 + 1 = 22

Thus, XLIV - XVII - XXII = 44 - 17 - 22 = 5 = V.

Suggest Corrections

Similar questions

Q. Mark against the correct answer
Which of the following is not meaningful?
(a) XIV
(b) XVV
(c) XIII
(d) XXII

Q. Compare XXII &

12 (using >, <, =)

Q. Compare

X X I I

12

(using

>, <, =

)

Q. Find the square root of each of the following correct to three places of decimal.
(i) 5
(ii) 7
(iii) 17
(iv) 20
(v) 66
(vi) 427
(vii) 1.7
(viii) 23.1
(ix) 2.5
(x) 237.615
(xi) 15.3215
(xii) 0.9
(xiii) 0.1
(xiv) 0.016
(xv) 0.00064
(xvi) 0.019
(xvii)

\frac{7}{8}

(xviii)

\frac{5}{12}

(xix)

2 \frac{1}{2}

(xx)

287 \frac{5}{8}

Q. Find equivalent weight of underline elements in the following compounds:
(i)

{F e - - -}_{2} O_{3}

(ii)

C a - - - O

(iii)

H B r - - -

(iv)

F e - - - O

(v)

{A g - - -}_{2} S

(vi)

{A l - - -}_{2} O_{3}

(vii)

M g - -- - C l_{2}

(viii)

C u - -- - O

(ix)

{C u - -- -}_{2} C l_{2}

(x)

P b - - - O

(xi)

P b - - - O_{2}

(xii)

{P b - - -}_{3} O_{4}

(xiii)

F e_{3} O_{4}

(xiv)

{P H - -- -}_{3}

(xv)

{N - -}_{3} H

(xvi)

{F e - - -}_{0.93} O

(xvii)

{S n - - -}_{4.44} O_{8}

(xviii)

C a - - - H_{2}

(xix)

{P - -}_{2} H_{4}

(xx)

S n - - - O_{2}

Join BYJU'S Learning Program

XLIV - XVII - XXII = ______

The correct option is D VLet us first convert the given Roman numerals into Hindu-Arabic numerals. XLIV = 50 - 10 + 4 = 44 XVII = 10 + 5 + 1 + 1 = 17 XXII = 10 + 10 + 1 + 1 = 22 Thus, XLIV - XVII - XXII = 44 - 17 - 22 = 5 = V.

The correct option is D V
Let us first convert the given Roman numerals into Hindu-Arabic numerals.

XLIV = 50 - 10 + 4 = 44
XVII = 10 + 5 + 1 + 1 = 17
XXII = 10 + 10 + 1 + 1 = 22

Thus, XLIV - XVII - XXII = 44 - 17 - 22 = 5 = V.