$x N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + y H_{2} O$ . Balance the given chemical equation and find the value of $x$ and $y$ .

2, 1

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2, 2

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2, 3

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1, 2

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Solution

The correct option is C $2, 2$
Atoms Left-hand side
Right-hand side
$N a$ $x$ $2$
$S$ $1$ $1$
$O$ $x + 4$ $y + 4$
$H$ $x + 2$ $2 \times y$
For the reaction:
$x N a O H + H_{2} S O_{4} \to {N a}_{2} S O_{4} + y H_{2} O$
Balance number of atoms on both sides of the reaction:
$x = 2$
therefore from above relations we get $x = y = 2$
balanced reaction is:
$2 N a O H + H_{2} S O_{4} \to {N a}_{2} S O_{4} + 2 H_{2} O$
Option $B$ is correct.

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Similar questions

N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O

N a O H + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O

NaOH + H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + H_{2} O

x N a + O_{2} \to y N a_{2} O

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + y H_{2} O

y H_{2} O_{2} \to 2 H_{2} O + O_{2}

2 A l + 2 H_{3} P O_{4} \to 2 A l P O_{4} + z H_{2}

C a (O H)_{2} + 2 H C l \to C a C l_{2} + y H_{2} O

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