XP and XQ are tangents from an outside point X. If XP = 8 cm and ∠PXQ = 600, find the length of the chord.
4
8
8√2
7
The triangle formed is an equilateral triangle. So AB = 8 cm.
In figure, XP and XQ are two tangents to a circle with center O from a point X outside the circle. ARB is tangent to circle at R. Prove that XA + AR = XB + BR.