Question

$\underset{\left(2\right)C{H}_{2}OH}{\overset{\left(1\right)HCI}{\to }}\times \underset{\left(2\right)H_{2}O}{\overset{\left(1\right)LiAI{H}_4/E{t}_{2}O}{\to }}Y\stackrel{H_O^{+}}{\to }Z,$ Identify X,Y and Z
(according to the image shown, the correct ans is)

Answer 1

In presence of HCl, carbonyl group reacts with ethylne glycol to form cyclic acetal which is product X.
The ester group $(-COO{C}_2{H}_5)$ is reduced to alcohol $(-C{H}_{2}OH)$ by using lithium aluminum hydride to form compound Y. This on hydrolysis in acidic medium breaks the cyclic acetal and regenerates the carbonyl group to give compound Z.