−→→A −→→B
|→A|=2units and |→B|=5units as shown above.
Find →A−→B
As →A−→B=→A+(−→B)
=→A=2^i,→B=5^i,−→B=−5^i
∴→A+(−→B)=2^i+(−5^i)
=−3^i
Graphically,
→A−→ →B−→ −→B←−−
∴→A+(−→B)=
∴→A−→B has a magnitude of 3 units in the negative x direction.
Vector A has magnitude of 5 units and makes an angle of 30∘ with the x-axis. Vector B has magnitude 10 units & make an angle of 60∘ with the x-axis. Find →A+→B
If A(-4 , 3) & B(8 , -6) have respective coordinates
a) find the length of AB,
b) the ratio in which the – axis divides AB.