Question 86 (xv)
Using suitable identities, evaluate the following:
10.1×10.2
We have, 10.1×10.2=(10+0.1)(10+0.2)=(10)2+(0.1+0.2)10+(0.1)(0.2)=100+0.3×10+0.02 =103.02 [using the identity, (x+a)(x+b)=x2+(a+b)x+ab]
Question 86 (xiv)
9.8×10.2
Question 86 (i)
(52)2
Question 86 (v)
(1005)2
Question 86 (iv)
(98)2