Question

Question 83 (xvii)

Multiply the following:
(pq - 2r), (pq - 2r)

Answer 1

We have, (pq - 2r) and (pq - 2r)
$\therefore (pq-2r)(pq-2r)=pq(pq-2r)-2r(pq-2r)$
$=p^2{q}^2-2pqr-2rpq+4r^2=p^2{q}^2-4pqr+4r^2$