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Question 92 (xviii)

Factorise the following using the identity a2b2=(a+b)(ab).

a4(ab)4


Solution

a4(ab)4=(a2)2[(ab)2]2=[a2+(ab)2][a2(ab)2]=[a2+a2+b22ab][a2(a2+b22ab)]=[2a2+b22ab][b2+2ab]=(2a2+b22ab)(2abb2)


Mathematics
NCERT Exemplar
Standard VIII

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