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Question

(xy2+2z)×2xy=

A
=2x2y3+4xyz
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B
2x3y2+4xyz
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C
=2x2y3+2xyz
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Solution

The correct option is A =2x2y3+4xyz
Using distributive law of multiplication i.e.
[a×(b+c)=ab+bc]
(xy2+2z)×2xy can be expressed as:
=xy2×2xy+2z×2xy
Applying commutative law and adding exponents of respective unknowns,
xy2×2xy+2z×2xy
=2×x(1+1)×y(2+1)+(2×2)×xyz
=2x2y3+4xyz

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