The correct option is A =2x2y3+4xyz
Using distributive law of multiplication i.e.
[a×(b+c)=ab+bc]
(xy2+2z)×2xy can be expressed as:
=xy2×2xy+2z×2xy
Applying commutative law and adding exponents of respective unknowns,
xy2×2xy+2z×2xy
=2×x(1+1)×y(2+1)+(2×2)×xyz
=2x2y3+4xyz