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Applying NLM along 3 Axis

XY2 dissociat...

Question

${X Y}_{2}$ dissociates as
${X Y}_{2} (g) ⇌ X Y (g) + Y (g)$
Initial pressure of ${X Y}_{2}$ is $600 m m$ $H g$ . The total pressure at equilibrium is $800 m m$ $H g$ .
Assuming volume of system to remain constant, the value of $K_{p}$ is:

50

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100

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400

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Solution

The correct option is A $100$
Answer $B .$
$X Y_{2} (g) ⇌ X Y (g) + Y (g) 600 m m 00 ⟵ I n i t i a l 600 - P 200200 ⟵ E q n$
$P_{T} = 800 m m ⟹$ $600 - P + 400 = 800 P = 200$
$∴ P_{X Y_{2}} = 600 - 200 = 400 m m$
$K_{P} = \frac{P_{Y} P_{X Y}}{P_{X Y_{2}}} = \frac{200 \times 200}{400} = 100$

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