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Factors Affecting Alpha

XY2 dissociat...

Question

$X Y_{2}$ dissociates as $X Y_{2} (g) ⇌ X Y (g) + Y (g)$ when the initial pressure of $X Y_{2}$ is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.

50 mm Hg

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100 mm Hg

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166.6 mm Hg

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400 mm Hg

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Solution

The correct option is B 100 mm Hg
$X Y_{2}$ dissociates as:
$X Y_{2} (g) ⇌ X Y (g) + Y (g)$
Initial pressure of $X Y_{2}$ is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg.

Let x mm Hg of $X Y_{2}$ dissociates to reach equilibrium. x mm Hg of XY and x mm Hg of Y will be formed at equilibrium. 600 - x mm Hg of $X Y_{2}$ will be present at equilibrium.

Total pressure $= (600 - x) + x + x = 600 + x m m H g$

But total pressure = 800 mm Hg
$600 + x = 800 o r x = 200$

Thus, the equilibrium pressures are
$P_{X Y_{2}} = 600 - x = 600 - 200 = 400 m m H g$
$P_{X Y} = x = 200 m m H g$
$P_{Y} = x = 200 m m H g$

Assuming volume of system to remain constant, the value of $K_{p} = \frac{P_{X Y} P_{Y}}{P_{X Y_{2}}}$

$K_{p} = \frac{200 \times 200}{400}$
$K_{p} = 100 m m H g$

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Similar questions

X Y_{2}

dissociates as:

X Y_{2} (g) ⇌ X Y (g) + Y (g)

When the initial pressure of

X Y_{2}

is 600 mm

H g

, the total equilibrium pressure is 800 mm

H g

. Calculate

K

for the reaction assuming that the volume of the system remains unchanged.

X Y_{2}

dissociates

X Y_{2} (g) ⇌ X Y (g) + Y (g)

. When the initial pressure of

X Y_{2}

600

mm Hg, the total equilibrium pressure is

800

mm Hg. Calculate

K

for the reaction. Assuming that the volume of the system remains unchanged :

X Y_{2}

dissociates as

X Y_{2} (g) ⇌ X Y (g) + Y (g)

when the initial pressure of

X Y_{2}

is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.

X Y_{2}

dissociates as:

X Y_{2} (g) ⇌ X Y (g) + Y (g)

Initial pressure of

X Y_{2}

600 m m

H g

. The total pressure at equilibrium is

800 m m

H g

. Assuming volume of system to remain constant, the value of

K_{p}

is:

X Y_{2}

dissociates as

X Y_{2 (g)} ⇌ X Y_{(g)} + Y_{(g)}

. When the initial pressure is

600

mm of Hg, the total pressure at equilibrium developed is

800

mm of Hg.

Therefore, the pressure of

Y

at equilibrium is:

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Factors Affecting Alpha

Standard XII Chemistry

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XY2 dissociates as XY2(g)⇌XY(g)+Y(g) when the initial pressure of XY2 is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.

$X Y_{2}$ dissociates as $X Y_{2} (g) ⇌ X Y (g) + Y (g)$ when the initial pressure of $X Y_{2}$ is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.