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Standard XII

Chemistry

Characteristics of Equilibrium Constant

XY2 g dissoci...

Question

$X Y_{2}$ (g) dissociates as $X Y (g) + Y (g)$ . When the initial pressure is 600 mm of Hg, the total pressure at equilibrium developed is 800 mm of Hg. Therefore pressure of Y at equilibrium is

200

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100

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150

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Solution

The correct option is A 200
$\begin{matrix} I n i t i a l p r e s s u r e & x y_{2} (g) 600 m m & ⇌ & x y (g) & + & y (g) a t e q u i l i b r i u m & 600 - p^{1} & p^{1} & p^{1} \end{matrix}$
Total pressure at equilibrium $= 600 - p^{1} + p^{1} + p^{1}$
$= 600 + p^{1}$
$600 + p^{1} = 800$
$p^{1} = 800 - 600 = 200 mm of Hg$

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Similar questions

X Y_{2}

(g) dissociates as

X Y (g) + Y (g)

. When the initial pressure is 600 mm of Hg, the total pressure at equilibrium developed is 800 mm of Hg. Therefore pressure of Y at equilibrium is

X Y_{2}

dissociates as

X Y_{2 (g)} ⇌ X Y_{(g)} + Y_{(g)}

. When the initial pressure is

600

mm of Hg, the total pressure at equilibrium developed is

800

mm of Hg.

Therefore, the pressure of

Y

at equilibrium is:

X Y_{2}

dissociates as

X Y_{2} (g) ⇌ X Y (g) + Y (g)

when the initial pressure of

X Y_{2}

is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.

X Y_{2}

dissociates as,

X Y_{2} (g) ⇌ X Y (g) + Y (g)

Initial pressure of

X Y_{2}

600 m m H g

. The total pressure at equilibrium is

800 m m H g

. Assuming volume of system to remain constant, the value of

K_{p}

is:

$X Y_{2}$ dissociates as,
$X Y_{2} (g) ⇌ X Y (g) + Y (g)$
Initial pressure of $X Y_{2}$ is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of $K_{P}$ is

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Characteristics of Equilibrium Constant

Standard XII Chemistry

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XY2 (g) dissociates as XY (g)+Y (g). When the initial pressure is 600 mm of Hg, the total pressure at equilibrium developed is 800 mm of Hg. Therefore pressure of Y at equilibrium is

The correct option is A 200Initialpressurexy2 (g)600mm⇌xy (g)+y (g)at equilibrium600−p1p1p1 Total pressure at equilibrium =600−p1+p1+p1 =600+p1 600+p1=800 p1=800−600=200 mm of Hg

$X Y_{2}$ (g) dissociates as $X Y (g) + Y (g)$ . When the initial pressure is 600 mm of Hg, the total pressure at equilibrium developed is 800 mm of Hg. Therefore pressure of Y at equilibrium is