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Question

xydydx=x2y2

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Solution

xydydx=x2y2
dydx=x2y2xy y=vx, dydx=v+xdvdx
v+xdvdx=vy[x2v2x2x2v]
xdvdx=x2x2(1v2v)v
xdvdx=1v2v2v
1(y)(y)vdv12v2=dxx.

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