wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

xydydx=x2y2

Open in App
Solution

xydydx=x2y2
dydx=x2y2xy y=vx, dydx=v+xdvdx
v+xdvdx=vy[x2v2x2x2v]
xdvdx=x2x2(1v2v)v
xdvdx=1v2v2v
1(y)(y)vdv12v2=dxx.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General and Particular Solutions of a DE
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon