$x y (x^{2} - 2 x + y^{2})$ and find its value for $x = - 1, y = 1$

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Solution

We have,
$x y (x^{2} - 2 x + y^{2})$

Since, $x = - 1, y = 1$

So,
$\Rightarrow (- 1) \times 1 ((- 1)^{2} - 2 (- 1) + 1^{2})$

$\Rightarrow - 1 (1 + 2 + 1)$

$\Rightarrow - 1 (4)$

$\Rightarrow - 4$

Hence, this is the answer.

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