wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

XYZ is an equilateral triangle and PQRS is a square. The figure has been cut and re-arranged in the form of a trapezium.

What is the length of the path ADCB in the trapezium ABEF?


A

12 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

17 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

16 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

14 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

16 cm


In the trapezium ABEF,

AD = 4 cm, since this is the equal side of Orange triangle which is equal to 4 cm.

DB = 8 cm, since this is the hypotenuse of Blue triangle which is equal to hypotenuse of Yellow triangle, as it is given as equilateral triangle all the sides must be equal.

BC = 4 cm, since BC and AD are equal in trapezium .

Length of the path ADBC = AD + DB + BC
= 4 + 8 + 4
= 16 cm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Perimeter of Plane Figures
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon