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Question
XYZ is an equilateral triangle and PQRS is a square. The figure has been cut and re-arranged in the form of a trapezium.
What is the length of the path ADCB in the trapezium ABEF?
XYZ is an equilateral triangle and PQRS is a square. The figure has been cut and re-arranged in the form of a trapezium.
What is the length of the path ADCB in the trapezium ABEF?
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Solution
The correct option is C 16 cm
In the trapezium ABEF,
AD = 4 cm, since this is the equal side of Orange triangle which is equal to 4 cm.
DB = 8 cm, since this is the hypotenuse of Blue triangle which is equal to hypotenuse of Yellow triangle, as it is given as equilateral triangle all the sides must be equal.
BC = 4 cm, since BC and AD are equal in trapezium .
Length of the path ADBC = AD + DB + BC
= 4 + 8 + 4
= 16 cm
16 cm
In the trapezium ABEF,
AD = 4 cm, since this is the equal side of Orange triangle which is equal to 4 cm.
DB = 8 cm, since this is the hypotenuse of Blue triangle which is equal to hypotenuse of Yellow triangle, as it is given as equilateral triangle all the sides must be equal.
BC = 4 cm, since BC and AD are equal in trapezium .
Length of the path ADBC = AD + DB + BC
= 4 + 8 + 4
= 16 cm
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