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Question

y2+2y3=?(a) (y1)(y+3)(b) (y+1)(y3)(c) (y1)(y3)(d) (y+2)(y3)


Solution

y2+2y3=y2+3yy3          {3=3×(1)2=31}=y(y+3)1(y+3)=(y+3)(y1)


Mathematics
Secondary School Mathematics VIII
Standard VIII

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