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Question

y2=4ax be the equation of a parabola, then

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Solution

For the parabola y2=4ax,
A) Equation of the tangent at (x1,y1) is yy1=2a(x+x1)
B) Equation of the normal at (x1,y1) is yy1=y12a(xx1)
xy1=2a(y1y)+x1y1
C) Equation of the focal chord through (x1,y1) and focus (a,0) is
y=y10x1a(xa)xy1=y(x1a)+ay1
D) Equation of the line joining (a,0), the point of intersection of the axis y=0 and the directrix x+a=0 with (x1,y1) is (x+a)y1=(x1+a)y

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