$y^{2} = 6 x^{3} + x - 8$ find $\frac{d y}{d x}$

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Solution

$y^{2} = 6 x^{3} + x - 8 \frac{d}{d x} y^{2} = \frac{d}{d x} 6 x^{3} + x - 8 2 y \frac{d y}{d x} = 18 x^{2} + 1 \frac{d y}{d x} = \frac{18 x^{2} + 1}{2 y}$

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