Question

y –$\frac{5}{y}$ = 3y – 7

Answer 1

Given: y –$\frac{5}{y}$ = 3y – 7
On multiplying both sides by y, we get:
y² – 5 = 3y² – 7y
On transposing all the terms of the right-hand side to the left-hand side, we get:
y² – 5 – 3y² + 7y = 0
=> – 2y² + 7y – 5 = 0
=> 2y² – 7y + 5 = 0
Thus, the standard form of the given quadratic equation is 2y² – 7y + 5 = 0.
On comparing this equation with ay² + by + c = 0 in variable y, we get:
a = 2, b = –7 and c = 5