Byju's Answer
Standard VII
Mathematics
Addition of Algebraic Expression
y-6=1 / 6 x3 ...
Question
y-6=1/6x
3/4x=1+y
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Solution
y-6=x/6
y-x/6=6
6y-x=36---->(1)
3x/4=1+y
3x/4-y=1
3x-4y=4----->(2)
equating 1 and 2
14y=112
y=8
substitute in eq 1 we get
6x8-x=36
x=48-36=12
x=12 and y=8
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