Y 7 completely divides y 9-2 y 8-4-A- TrueB- False

The correct option is B FalseWe see from the above that nbsp;y^9+2y^8+4 when divided by y^7 leaves a remainder 4. nbsp; Therefore, nbsp;y^7 does not comp ...

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Byju's Answer

Standard VIII

Mathematics

Division of a Polynomial by a Binomial

y 7 completel...

Question

$y^{7}$ completely divides $y^{9} + 2 y^{8} + 4$ .

True

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False

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Solution

The correct option is B False
We see from the above that $y^{9} + 2 y^{8} + 4$ when divided by $y^{7}$ leaves a remainder 4.
Therefore, $y^{7}$ does not completely divide $y^{9} + 2 y^{8} + 4$ .
Hence, the given statement is false.

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Similar questions

Q. What is the value of remainder when

y^{9} + 2 y^{8} + 4

is divided by

y^{7}

4 x^{2}

completely divides

8 x^{6} - 12 x^{3}

14 m^{2}

completely divides

42 m^{3}

Q. Factor out the greatest common factor. Simplify the factors, if possible.

96 x^{8} y^{9} - 60 x^{3} y^{7} + 84 x^{6} y^{4}

Q. Divide:

(x^{8} y^{7} z^{6} - z^{6} y^{7} x^{8})

y^{7} x^{8} z^{6}

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y7 completely divides y9+2y8+4.

The correct option is B FalseWe see from the above that y9+2y8+4 when divided by y7 leaves a remainder 4. Therefore, y7 does not completely divide y9+2y8+4. Hence, the given statement is false.

$y^{7}$ completely divides $y^{9} + 2 y^{8} + 4$ .

The correct option is B False
We see from the above that $y^{9} + 2 y^{8} + 4$ when divided by $y^{7}$ leaves a remainder 4.
Therefore, $y^{7}$ does not completely divide $y^{9} + 2 y^{8} + 4$ .
Hence, the given statement is false.