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Question

y=x4+x2+1x2+x+1;dydx=ax+bFinda3+b3

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Solution

x4+x2+1x2+x+1=(x2+x+1)22x(x2+x+1)x2+x+1y=x2+x+12xdydx=2x+12=2x1a=2,b=1a3+b3=23+(1)3=81=7

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