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Byju's Answer
Standard VI
Mathematics
Formation of Algebraic Expressions
y=∫√x3-1-3x2+...
Question
y
=
∫
√
(
x
3
−
1
−
3
x
2
+
3
x
)
x
−
1
d
x
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Solution
We have,
y
=
∫
√
(
x
3
−
1
−
3
x
2
+
3
x
)
x
−
1
d
x
y
=
∫
√
(
x
−
1
)
3
x
−
1
d
x
y
=
∫
√
(
x
−
1
)
2
d
x
y
=
∫
(
x
−
1
)
d
x
y
=
x
2
2
−
x
+
C
Hence, this is the answer.
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