$y = e^{- 2 x}$ is a solution of the differential equation $y^{''} + y^{'} - 2 y = 0$

True

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False

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Solution

The correct option is A True
$y^{''} + y^{'} - 2 y = 0$
$A . E$ is $D^{2} + D - 2 = 0$
$D = - 2, 1$
$y = e^{- 2 x}$ and $y = e^{x}$ are
The solutions of the given diferential equation.

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