Question

Y g of non-volatile organic substance of molar mass M is dissolved in 250 g benzene. Molal elevation constant of benzene is $K_b$. Elevation in its boiling point is given by :

• A. $\frac{M}{K_{b}Y}$
• B. $\frac{4K_{b}Y}{M}$
• C. $\frac{K_{b}Y}{4M}$
• D. $\frac{K_{b}Y}{M}$

Answer 1

The correct option is B $\frac{4K_{b}Y}{M}$

Elevation in its boiling point is given by

$\Delta T=\frac{1000\times K_b\times Y}{250\times M}$

$=$$\frac{4K_{b}Y}{M}$

Hence, the correct option is $B$