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Equation of Family of Circles Which Are Concentric

y = mx is a c...

Question

y = mx is a chord of a circle of radius a and the diameter of the circle lies along x-axis and one end of this chord in origin .The equation of the circle described on this chord as diameter is

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Solution

The correct option is B

Here the equation of circle is

$(x - a)^{2} + (y - 0)^{2} = a^{2} \Rightarrow x^{2} + y^{2} - 2 a x = 0$

Suggest Corrections

Similar questions

y = m x

a

x

(1 + m^{2}) (x^{2} + y^{2}) - 2 a (x + m y) = 0

x^{2} + y^{2} - 2 a x = 0

x^{2} + y^{2} - 2 a x = 0

y^{2} = 4 a x

y^{2} = 2 a (x - a)

A (a t_{1}^{2}, 2 a t_{1})

B (a t_{2}^{2}, 2 a t_{2})

y^{2} = 4 a x,

t_{1} t_{2} = - 1

x^{2} + y^{2} + 2 a x + c = 0

x^{2} + y^{2} + 2 b y + c = 0

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