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Byju's Answer
Standard XII
Mathematics
First Principle of Differentiation
y=sin-1[log3x...
Question
y
=
sin
−
1
[
log
3
(
x
3
)
]
⇒
−
1
≤
log
3
(
x
3
)
≤
1
Open in App
Solution
y
=
sin
−
1
[
log
3
(
x
3
)
]
−
1
≤
log
3
(
x
3
)
≤
1
1
3
≤
(
x
3
)
≤
3
1
≤
x
≤
9
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0
Similar questions
Q.
Solve the following equation:
log
3
(
x
+
1
)
+
log
3
(
x
+
3
)
=
1
Q.
Solve the following equations and find the solution:
log
3
(
x
+
1
)
+
log
3
(
x
+
3
)
=
1
Q.
Find the domains of definition of the following function:
y
=
1
3
−
log
3
(
x
−
3
)
.
Q.
If
log
3
(
x
3
−
x
2
−
x
+
1
)
−
log
3
(
x
−
1
)
−
log
3
(
x
+
1
)
=
2
, then
x
=
Q.
Solve for
x
:
l
o
g
3
(
x
3
)
+
l
o
g
1
/
9
(
x
)
<
1
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