CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

y=xa+ax,provethat2xydydx=(xaax)

Open in App
Solution

We have,
y=xa+ax

Squaring both sides,
y2=xa+ax+21

y2=xa+ax+2

On differentiating w.r.t x, we get
2ydydx=1aax2+0

2ydydx=1aax2

2xydydx=xaax

Hence, proved.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Square Roots of Perfect Squares
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon