$y = x tan x$ Find $\frac{d y}{d x}$

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Solution

$y = x tan x \frac{d y}{d x} = \frac{d}{d x} x tan x \frac{d y}{d x} = tan x \frac{d x}{d x} + x \frac{d tan x}{d x} \frac{d y}{d x} = tan x + x {sec}^{2} x$

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