Y - xy - yz 2-2 x 2 y 2 zWhen x -1- y -1 and z -2- Y -A- 3B- 5C- 7D- 1

The correct option is A 3 Y = (xy+yz)^2 using the identity (a+b)^2 nbsp;= a^2+ b^2 nbsp;+ 2ab We get (xy+yz)^2=x^2y^2 nbsp;+ y^2z^2 nbsp;+ 2xzy^2. Ther ...

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Byju's Answer

Standard IX

Mathematics

Polynomial Expressions

Y = xy + yz 2...

Question

Y = $(x y + y z)^{2} - 2 x^{2} y^{2} z$
When $x = - 1, y = 1$ and $z = 2$ , |Y| = ___

-3

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Solution

The correct option is B
3

Y = ${(x y + y z)}^{2}$ using the identity
${(a + b)}^{2} = a^{2} + b^{2} + 2 a b$
We get ${(x y + y z)}^{2} = x^{2} y^{2} + y^{2} z^{2} + {2 x z y}^{2}$ .

Therefore,
${(x y + y z)}^{2} - 2 x^{2} y^{2} z = x^{2} y^{2} + y^{2} z^{2} + 2 x z y^{2} - 2 x^{2} y^{2} z$

Placing the values of $x$ , $y$ and $z$ in the above expression, we get
1 + 4 - 4 - 4 = -3
|Y| = |-3| = 3

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Similar questions

Y = $(x y + y z)^{2} - 2 x^{2} y^{2} z$
When $x = - 1, y = 1$ and $z = 2$ , |Y| = ___

Simplify $(x y + y z)^{2} - 2 x^{2} y^{2} z .$
Find the value when $x = - 1, y = 1$ and $z = 2$ .

Simplify $(x y + y z)^{2}$ $- 2$ $x^{2}$ $y^{2}$ z. Find the value when $x = - 1, y = 1$ and $z = 2$ .

Q. Simplify

(x y + y z)^{2} - 2 x^{2} y^{2} z .

Find the value when

x = - 1, y = 1

and

z = 2

Simplify $(x y + y z)^{2} - 2 x^{2} y^{2} z$ and find the value when $x = - 1, y = 1$ and $z = 2.$

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Y = (xy+yz)2−2x2y2z When x=−1,y=1 and z=2, |Y| = ___

The correct option is B 3 Y = (xy+yz)2 using the identity (a+b)2=a2+b2+2ab We get (xy+yz)2=x2y2+y2z2+2xzy2. Therefore, (xy+yz)2−2x2y2z=x2y2+y2z2+2xzy2−2x2y2z Placing the values of x,y and z in the above expression, we get 1 + 4 - 4 - 4 = -3 |Y| = |-3| = 3

Y = $(x y + y z)^{2} - 2 x^{2} y^{2} z$
When $x = - 1, y = 1$ and $z = 2$ , |Y| = ___