Question

y² – 16y + 63 = 0

Answer 1

Given: y² – 16y + 63 = 0
On splitting the middle term –16y as – 9y – 7y, we get:
y² – 9y – 7y + 63 = 0
=> y(y – 9) – 7(y – 9) = 0
=> (y – 9) (y – 7) = 0
We know that if the product of two numbers is zero then at least one of them must be zero.
Thus,
y – 9 = 0 or y – 7 = 0
=> y = 9 or y = 7
Therefore, the solution of the given equation is y = 9, 7.