Yellow ammonium sulphide ( $Y A S$ ) can be used to separate $S n S$ and ${A s}_{2} S_{3}$ .

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Solution

Group $I I B$ sulphides react with yellow ammonium sulphide to form thiosalts. These thiosalts reacts with HCl to form coloured precipitates.

$A s_{2} S_{3}$ is yellow in colour and $S n S$ is brown in colour.

$2 (N H_{4})_{3} s o l u b l e A s S_{4} + 6 H C l ⟶ A s_{2} S_{6} ↓ + 6 N H_{4} C l + 3 H_{2} S$

$(N H_{4})_{2} S n S_{3} + 2 H C l ⟶ S n S_{2} ↓ + 2 N H_{4} C l + H_{2} S$

$S n S$ and ${A s}_{2} S_{3}$ both are soluble in $Y A S$ . Hence, the given statement is not true.

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