Yellow light is refracted through a prism producing minimum deviation. If $i_{1}$ and $i_{2}$ denote the angle of incidence and emergence for this prism, then

i_{1} = i_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

i_{1} > i_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i_{1} < i_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i_{1} + i_{2} = 90^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $i_{1} = i_{2}$
For minimum (or zero) deviation incident ray and emergent ray should be parallel to each other, which is possible when $i_{1} = i_{2}$

Suggest Corrections

Similar questions

Now what should be the correct relation between $I_{1}$ , $I_{2}$ and $I_{3}$ .

I_{1} = π / 2 \int 0 cos (sin x) d x; I_{2} = π / 2 \int 0 sin (cos x) d x

I_{3} = π / 2 \int 0 cos x d x,

I_{1} = 1 \int 0 e^{- x} {cos}^{2} x d x

I_{2} = 1 \int 0 e^{- x^{2}} {cos}^{2} x d x

I_{3} = 1 \int 0 e^{- x^{3}} d x

If $I_{1} = \int_{0}^{\frac{π}{2}} x s i n x d x & I_{2} = \int_{0}^{\frac{π}{2}} x c o s x d x$ , then which of the following is true?

I_{1}

I_{2}

x

Join BYJU'S Learning Program