Question

YOU ARE GIVEN 500ml OF 2N HCL AND 500ml OF 5N HCL. WHAT WILL BE THE MAXIMUM VOLUME OF 3M HCL THAT YOU CAN MAKE FROM THESE SOLUTION?

Answer 1

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When 2 solutions of molarities M1 and M2 and volumes V1 and V2 are mixed together, the new molarity M is equal to,
M= (M1V1+ M2V2)/ (V1+V2)

We have, Normality= Molarity* Acidity or Basicity
Since HCl is a monobasic acid, or a monoprotic acid, that is it releases only 1 hydronium ion in solution, it's normality= molarity* 1
So normality and molarity are equal in this case.

therefore rearranging the above equation, we get
the total volume, (V1+V2)= (M1V1+ M2V2) / M
= (N1V1 + N2V2) / N
= (2* 500 + 5*500) / 3
= 3500/ 3
= 1166 mL