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Byju's Answer

Standard IX

Mathematics

Rolling of Dice Experiment

You are given...

Question

You are given a box with 20 cards in it 10 of these cards have the letter I printed on them, the other ten have the letter T printed on them, if you pick up 3 cards at random and keep them in the same order the probability of making the IIT is

\frac{9}{80}

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\frac{1}{8}

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\frac{4}{27}

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\frac{5}{38}

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Solution

The correct option is C $\frac{5}{38}$
As we have to consider order for IIT, the required probability
$= \frac{10}{20} \times \frac{9}{19} \times \frac{10}{18} = \frac{5}{38} .$

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You are given a box with 20 cards in it 10 of these cards have the letter I printed on them, the other ten have the letter T printed on them, if you pick up 3 cards at random and keep them in the same order the probability of making the IIT is

The correct option is C 538As we have to consider order for IIT, the required probability =1020×919×1018=538.

The correct option is C $\frac{5}{38}$
As we have to consider order for IIT, the required probability
$= \frac{10}{20} \times \frac{9}{19} \times \frac{10}{18} = \frac{5}{38} .$